Question

Construct the right angled $△PQR$ where $m\angle Q={90}^o$, $QR=8cm$ and $PR=10cm$.

Answer 1

To construct: A right angled $△PQR$ where $m\angle Q={90}^o$, $QR=8cm$ and $PR=10cm$.
Steps of construction:
(a) Draw a line segment $QR=8cm$
(b) At point $Q$, draw $QX\perp QR$
(c) Taking $R$ as centre, draw an arc of radius $10cm$
(d) This arc cuts $QX$ at point $P$
(e) Join $PQ$
It is the required right angled triangle $PQR$