MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Area of Trapezium by Division into Shapes of Known Area

Construct tra...

Question

Construct trapezium PQRS with the following measurement. Find also its area.
$¯ ¯¯¯¯¯¯ ¯ P Q$ is parallel to $¯ ¯¯¯¯¯¯ ¯ S R$ , PQ = 6.5 cm, QR = 7 cm, $∠$ PQR = $85^{o}$ PS = 9 cm.

Open in App

Solution

Area of PQRS = $\frac{1}{2} (P Q + S R) \times Q R$
= $\frac{1}{2} (6.5 + 12) \times 7$
= $64.75 {c m}^{2}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Construct a trapezium PQRS in which

¯ ¯¯¯¯¯¯ ¯ P Q

¯ ¯¯¯¯¯¯ ¯ S R

∠

70^{o}

, QR = 6 cm and PS = 6 cm. Calculate its area.

Q. Construct a cyclic quadrilateral PQRS, with PQ

= 6.5

= 5.5

= 7

= 4.5

Q. Construct a quadrilateral PQRS with PQ = 4 cm, QR = 6 cm, PR = 7 cm, PS = 5 cm and

∠

40^{o}

and find its area.

Q. In rectangle PQRS, l(PQ) = 7 cm and l(PS) = 9 cm. Find l(QR) and l(SR).

Q. PQRS is a trapezium such that PQ || RS and PQ = 10 cm, QR = 5 cm, RS = 8 cm and PS = 5 cm, then area of PQRS is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Trapezium

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Area of Trapezium by Division into Shapes of Known Area

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon