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Area of Trapezium by Division into Shapes of Known Area

Construct tra...

Question

Construct trapezium PQRS with the following measurement. Find also its area.
$¯ ¯¯¯¯¯¯ ¯ P Q$ is parallel to $¯ ¯¯¯¯¯¯ ¯ S R$ , PQ = 6.5 cm, QR = 7 cm, $∠$ PQR = $85^{o}$ PS = 9 cm.

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Solution

Area of PQRS = $\frac{1}{2} (P Q + S R) \times Q R$
= $\frac{1}{2} (6.5 + 12) \times 7$
= $64.75 {c m}^{2}$

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