Question

Construct $△ABC$ in which $BC=7cm,\angle B={75}^o$ and $AB+AC=12cm$

Answer 1

Draw a ray BX and cut of a line segment $BC=7cm$, from it.

AT B, construct angle $YBX={75}^0$.

With $B$ as center and radius $=12cm$ (because $AB+AC=12cm$

Draw an arc to meet $BY$ at $D$.

Join $CD$

Draw perpendicular bisector $PQ$ of $CD$ intersecting $BD$ at $A$.

Join $AC$

Then,

$ABC$ is the required triangle.