Question

Construct $△DEF$ with $DE=4cm,EF=5.5cm$ and $DF=5cm$.

Answer 1

Given that

$DE=4cm$

$=5.5cm$

$DF=5cm$

Step of construction

(i) Draw a line segment $EF=5.5cm$

(ii) With $F$ as centre and radius $5cm$ draw an arc

(iii) With $E$ as centre & radius $4cm$ draw another arc cutting the previous arc at $D$

(iv) Join $FD$ and $ED$ then triangle $DEF$ is the required triangle.