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Question

Construct DEF with EF=4.5 cm,DE=5 cm and DF=3 cm

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Solution

Given that
EF=4.5 cm
DE=5 cm
And,DF=5 cm
step of construction
(i) Draw a line segment DE=5 cm
(ii) With E as centre and radius 4.5 cm draw an arc.
(iii) With D as centre and radius 4 cm draw an arc cutting the previous arc at F
(iv) join EF and DF then ΔDEF is the required triangle

1081205_721337_ans_504cf3495ea74813bd4093a9adeea471.png

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