Question

Construct $△MNO$ where base $NO=6.7cm$, $\angle MNO={45}^{\circ }$ and $MO-MN=2.8cm.$

Answer 1

1. Draw $NO=6.7cm.$

2. Construct $\angle N={45}^{\circ }$ and produce it to $X.$

3. Cut off line segment $NP=2.8cm$ on $NX.$

4. Join $P-O$.

5. Draw a perpendicular bisector of $PO$ such that it intersects $NX$ at $M.$

6. Join $M-O$.

7. $MNO$ is the required triangle.