Question

Construct $△PQR$ with $PQ=4cm,QR=7cm$ and $PR=8cm$

Answer 1

Given that

$PQ=4cm$

$QR=7cm$

$PR=8cm$

step of construction

(i) Draw a line segment $PR=8cm$

(ii) With $R$ as center and radius $7cm$ draw an arc.

(iii) With $P$ as center and radius $4cm$ draw an arc cutting the previous arc at $Q$

(iv) join $RQ$ and $PQ$ then $\Delta PQR$ is the required triangle.