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Question

Construct $$\triangle PQR$$ with $$PQ=4cm, \,QR =7cm$$ and $$PR=8cm$$


Solution

Given that
$$PQ=4cm$$
$$QR=7cm$$
$$PR=8cm$$
step of construction

(i) Draw a line segment $$PR=8cm$$

(ii) With $$R$$ as center and radius $$7cm$$ draw an arc.

(iii) With $$P$$ as center and radius $$4cm$$ draw an arc cutting the previous arc at $$Q$$

(iv) join $$RQ$$ and $$PQ$$ then $$\Delta PQR$$ is the required triangle.

1081169_721336_ans_fec937d953ad498db051aaeb8da1e497.PNG

Mathematics

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