Question

# Construct $$\triangle PQR$$ with $$PQ=4cm, \,QR =7cm$$ and $$PR=8cm$$

Solution

## Given that$$PQ=4cm$$$$QR=7cm$$$$PR=8cm$$step of construction(i) Draw a line segment $$PR=8cm$$(ii) With $$R$$ as center and radius $$7cm$$ draw an arc.(iii) With $$P$$ as center and radius $$4cm$$ draw an arc cutting the previous arc at $$Q$$(iv) join $$RQ$$ and $$PQ$$ then $$\Delta PQR$$ is the required triangle.Mathematics

Suggest Corrections

0

Similar questions
View More