Construct $△ X Y Z$ with $X Y = 4 c m, y z = 6 c m$ and $Z X = 3 c m$

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Solution

Given that
$X Y = 4 c m$
$Y Z = 6 c m$
$Z X = 3 c m$
Step of construction
(i) Draw a line segment $Y Z = 6 c m$
(ii) With $Z$ as centre and radius $3 c m$ draw an arc
(iii)) with $Y$ as centre radius $4 c m$ draw another arc cutting the previous arc at $X$ .
(iv) Join $Z X$ and $Y X$ then $Δ X Y Z$ is the right angle triangle.

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