Construct $∆$ XYZ, in which YZ = 6 cm, XY + XZ = 9 cm. $∠$ XYZ = $50^{°}$

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Solution

Steps of constructions:

(1) Draw seg YZ of length 6 cm.
(2) Draw ray YV such that ∠ZYV = 50°.
(3) Mark point W on ray YV such that YW = 9 cm
(4) Draw seg WZ.
(5) Construct the perpendicular bisector of seg WZ .
(6) Name the point of intersection of ray YW and the perpendicular bisector of WZ as X.
(7) Draw seg XZ.
Therefore, △XYZ is the required triangle.

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Construct ∆ XYZ, in which YZ = 6 cm, XY + XZ = 9 cm. ∠XYZ = 50°

Construct $∆$ XYZ, in which YZ = 6 cm, XY + XZ = 9 cm. $∠$ XYZ = $50^{°}$