Construction of a Similar Triangle, When One Vertex Is Common
Construction ...
Question
Construction of a ΔA′C′B similar to ΔACB is shown in the figure below, which condition is used to construct A′C′ ||AC?
A
Corresponding angles are equal
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B
Alternate interior angles are equal
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C
Co-interior angles are supplementary
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D
Perpendicular bisector theorem
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Solution
The correct option is A Corresponding angles are equal Here we construct A′C′||AC by making ∠A′C′B=∠ACB and we used the corresponding angle property (if corresponding angles of two lines are equal, then the lines are parallel).