Question

Construction of isosceles triangle ABC is given below, where altitude = 4cm and $\angle A={90}^{\circ }$.Then $\Delta ABM$ is a/an:

• A. Isosceles triangle
• B. Right angled triangle
• C. Isosceles rightangle triangle
• D. Scalene triangle

Answer 1

The correct option is C Isosceles rightangle triangle

Given $\angle A={90}^{\circ }$, Therefore $\angle BAM={45}^{\circ }$ since $\Delta BAM\cong \Delta CAM$.
$\to \Delta ABM$ is an isosceles right triangle