Constuct an equilateral triangle , each of whose altitudes measures 5.4 cm. Measure each of its sides.
ANSWER:
Steps of construction:
1. Draw a line XY.
2. Mark any point P.
3. From P draw PQ ⊥ XY.
4. From P, set off PA = 5.4 cm, cutting PQ at A.
5. Construct ∠PAB = 30° and ∠PAC = 30°, meeting XY at B and C, respectively.
Thus, △ ABC is the required triangle. Measure of each side is 6 cm.