Contains carbon that are $s p^{2}$ hybridized:

C_{2} H_{5}

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C_{2} H_{4}

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C_{2} H_{2}

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C_{2} H_{5} O H

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C_{3} H_{8}

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Solution

The correct option is B $C_{2} H_{4}$
Ethene or $C_{2} H_{4}$ is $s p^{2}$ hybridized. Here, each carbon atom has three $s p^{2}$ hybridized orbitals. Two of them form sigma bonds with two Hydrogen atoms. While, the other form another sigma bond with the second carbon atom.
Thus option B is the correct answer.

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Similar questions

C_{2} H_{5}

C_{3} H_{8}

C_{3} H_{6}

C_{2} H_{2}

The data given below are for vapour phase reactions at constant pressure.

$C_{2} H_{6} \to {∙ C}_{2} H_{5} + ∙ H; Δ H = 420 k J m o l^{- 1}$

${∙ C}_{2} H_{5} \to C_{2} H_{4} + ∙ H; Δ H = 168 k J m o l^{- 1}$

The enthalpy change for the reaction for the given reaction is :

$2 {∙ C}_{2} H_{5} \to C_{2} H_{6} + C_{2} H_{4}$

C_{2} H_{5} - O - C_{2} H_{5} + H I ? \to C_{2} H_{5} - O H + C_{2} H_{5} - I

O H^{-}

C H_{3} - C H | C_{2} H_{5} - B r

C H_{3} - B r | C | C_{2} H_{5} - C H_{3}

C H_{3} - C H | C_{2} H_{5} - C H_{2} B r

{s p}^{2}

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