Continuing with the previous question, what angle do we have at the end of four arcs?
With B as the centre and any radius more than half of AB, draw another arc as shown. This is the third arc. With A as the centre and the same radius as above, cut the previously drawn arc in Y. This would be the fourth arc. Join PY.
What is the angle ∠ YPA?
30°
From B and A, we draw two arcs which intersect each other in Y. These arcs have the same radius so we have BY=AY,
since PB = PA, and PY = PY(common side)
By SSS congruency criterion, △ PBY ≅ △ PAY
So ∠ BPY = ∠ YPA = 12 ∠ BPA = 30∘