Question

Conventional flow of current will always be from -

• A. p type$\to$n type
• B. n type $\to$p type
• C. n Type $\to$ n type
• D. None of these

Answer 1

The correct option is A p type$\to$n type

The holes in the covalent bonds of p-type semiconductor. They appear to move towards n-type semiconductor. Because the electrons in the covalent bonds of n-type semiconductor (not free electrons) jump towards p-type semiconductor due to plenty of holes available in the covalent bonds at p-side.

Hence, conventional current flow from p-type to n-type.