Question

Converging rays are incident on a sphere of radius 10 cm $(\mu =1.4).$. in the absence of sphere the rays would have converged to 40 cm. Find the position of image

Answer 1

$\frac{1.4}{v}\frac{1}{40}-\frac{1.4-1}{10}orv-21.58cm$
Since the ray cross the sphere they will be refracted again.
$\frac{1}{v}-\frac{1.4}{1.58}=\frac{1-1.4}{-10}or\frac{1}{v}=\frac{1.4}{1.58}+\frac{.4}{10}or=\frac{15.8}{14+0.632}=1.08cmi.e.1.08cmfromp$