Conversion of base e to base 10 and viceversa-log e a -log 10 a -log 10 e -2-303 -log 10 alog 10 a -log e a -log e a -log 10 e -log e a -0-434 log e a

Log_e a = log_10a/log_10e = ( 1/log_10e )× log_10a=(log_e 10) × log_10a =2.303 × log_10a Now, log_10a = log_e a/log_e10 = (log_10e) × log_e a = 0.434 log_e a ...

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Quantitative Aptitude

Solving Inequalities

Conversion of...

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Conversion of base e to base 10 and viceversa:
$l o g_{e} a = \frac{l o g_{10} a}{l o g_{10} e} = 2.303 \times l o g_{10} a$
$l o g_{10} a = \frac{l o g_{e} a}{l o g_{e} a} = l o g_{10} e \times l o g_{e} a = 0.434 l o g_{e} a$

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$l o g_{e} a = \frac{l o g_{10} a}{l o g_{10} e} = (\frac{1}{l o g_{10} e}) \times l o g_{10} a = (l o g_{e} 10) \times l o g_{10} a$
$= 2.303 \times l o g_{10} a$
Now, $l o g_{10} a = \frac{l o g_{e} a}{l o g_{e} 10} = (l o g_{10} e) \times l o g_{e} a = 0.434 l o g_{e} a$

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Conversion of base e to base 10 and viceversa: logea=log10alog10e=2.303×log10a log10a=logealogea=log10e×logea=0.434logea

logea=log10alog10e=(1log10e)×log10a=(loge10)×log10a =2.303×log10a Now, log10a=logealoge10=(log10e)×logea=0.434logea

Conversion of base e to base 10 and viceversa:
$l o g_{e} a = \frac{l o g_{10} a}{l o g_{10} e} = 2.303 \times l o g_{10} a$
$l o g_{10} a = \frac{l o g_{e} a}{l o g_{e} a} = l o g_{10} e \times l o g_{e} a = 0.434 l o g_{e} a$

$l o g_{e} a = \frac{l o g_{10} a}{l o g_{10} e} = (\frac{1}{l o g_{10} e}) \times l o g_{10} a = (l o g_{e} 10) \times l o g_{10} a$
$= 2.303 \times l o g_{10} a$
Now, $l o g_{10} a = \frac{l o g_{e} a}{l o g_{e} 10} = (l o g_{10} e) \times l o g_{e} a = 0.434 l o g_{e} a$