Conversion of $P b S O_{4}$ to $P b S$ is :

reduction of S

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oxidation of S

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dissociation

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none of these

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Solution

The correct option is B reduction of S
Explanation:
The oxidation number of $S$ in $P b S O_{4} = 6$
The oxidation number of $S$ in $P b S$ = $- 2$
So, the oxidation number is changes from $+ 6$ in $P b S O_{4}$ to $- 2$ in $P b S$ . Thus , sulphur is reduced.
The reaction is :
$P b S O_{4} + 2 C \to P b S + 2 C O_{2}$
Hence option A is correct answer

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