Conversion of sulphur dioxide to sulphuric acid

2 {S O}_{2} + {2 H}_{2} O \to 2 H_{2} {S O}_{4} + [H]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{S O}_{2} + {4 H}_{2} O \to 2 H_{2} {S O}_{4} + 2 [H]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{S O}_{2} + {2 H}_{2} O \to H_{2} {S O}_{4} + 2 [H]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 {S O}_{2} + {2 H}_{2} O \to 2 H_{2} {S O}_{4} + 2 [H]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${S O}_{2} + {2 H}_{2} O \to H_{2} {S O}_{4} + 2 [H]$
${S O}_{2} + {2 H}_{2} O \to H_{2} {S O}_{4} + 2 [H]$

Suggest Corrections

Similar questions

C + 2 H_{2} {S O}_{4} \to {C O}_{2} + {2 H}_{2} O + 2 {S O}_{2}

C u + 2 H_{2} {S O}_{4} ⟶ C u {S O}_{4} + {S O}_{2} + 2 H_{2} O

{2 S O}_{2} + O_{2} 450^{0} C - -- \to V_{2} O_{2} {2 S O}_{x} {S O}_{3} + H_{2} {S O}_{4} \to H_{2} S_{2} O_{y} H_{2} S_{2} O_{7} + H_{2} O \to 2 H_{2} {S O}_{4}

2 H_{2} {S O}_{4} 830^{o} C - --- \to {2 S O}_{x} + 2 H_{2} O + O_{2}

I_{2} + {S O}_{2} + {2 H}_{2} O 120^{o} C - -- \to z H I + H_{2} {S O}_{4}

2 H I 320^{o} C - -- \to y I_{2} + H_{2}

x, y

z

2 H_{2} S + S O_{2} ⟶ 2 H_{2} O + 3 S

1

S O_{2}

H_{2} S

Join BYJU'S Learning Program