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Introduction

Conversion of...

Question

Conversion of sulphur to $S O_{3}$ has $△ H = 2 x K c a l$ and conversion of $S O_{2}$ to $S O_{3}$ involves $△ H = - y k c a l$ . The correct thermochemical equation for formation of $S O_{2}$ is:

S + O_{2} \to S O_{2} △ H = (y - 2 x)

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S + O_{2} \to S O_{2} △ H = - (y - 2 x)

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S + O_{2} \to S O_{2} △ H = (x + y)

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S + O_{2} \to S O_{2} △ H = 2 y - 3 x

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Solution

The correct option is D $S + O_{2} \to S O_{2} △ H = (y - 2 x)$
Solution:- (A) $S + O_{2} ⟶ S O_{2}; Δ H = (y - 2 x) k c a l$
Given:-
$S + \frac{3}{2} O_{2} ⟶ S O_{3}; Δ H = - 2 x k c a l . . . . . (1)$
$S O_{2} + \frac{1}{2} O_{2} ⟶ S O_{3}; Δ H = - y k c a l$
$S O_{3} ⟶ S O_{2} + \frac{1}{2} O_{2}; Δ H = y k c a l . . . . . (2)$
Adding ${e q}^{n} (1) & (2)$ , we have
$S + \frac{3}{2} O_{2} + S O_{3} ⟶ S O_{3} + S O_{2} + \frac{1}{2} O_{2}; Δ H = [y + (- 2 x)] k c a l$
$S + O_{2} ⟶ S O_{2}; Δ H = (y - 2 x) k c a l$

Suggest Corrections

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