Convert $19200 k g / m^{3}$ into $g c m^{- 3}$ .

192 g c m^{- 3}

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1.92 g c m^{- 3}

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19.2 g c m^{- 3}

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1920 g c m^{- 3}

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Solution

The correct option is D $19.2 g c m^{- 3}$
$1 k g = 1000 g$
Conversion factor $= \frac{1000 g m}{1 k g}$
$1 m = 100 c m$
Conversion factor $= \frac{1 m}{100 c m}$
$∴ 19200 k g m^{- 3} = 19200 k g m^{- 3} \times \frac{1000 g}{1 k g} \times {(\begin{matrix} \frac{1 m}{100 c m} \end{matrix})}^{3}$
$= 19.200 g / c m^{3} = 19.2 g c m^{- 3}$

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