Question

Convert $-{40}^{o}F$ to the celsius scale.

Answer 1

Since,

$F=\frac{9}{5}\times C^o+32$

Given $T_{f^o}=-{40}^{o}F$

$\Rightarrow$ $-{40}^o-32=\frac{9}{5}\times C^o$

$\Rightarrow$ $-72\times \frac{5}{9}={}^{o}C$

$\Rightarrow$ $T_{C^o}=-{40}^{o}C$

Since, its the temperature at which celsius and Farenheit scale have same temperature.