Convert 400- C to Kelvin scale-A- 300 KB- 673-15 K- 126-85 KD- 0 K

The correct option is B 673.15 KUsing the temperature conversions: C nbsp;= 273.15 + nbsp; K where: C: Magnitude in Celcius Scale K: Magnitude in Kelvin Sc ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Physics

Temperature Scale

Convert 400∘ ...

Question

Convert $400^{\circ} C$ to Kelvin scale.

300 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

673.15 K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

126.85 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $673.15 K$
Using the temperature conversions:
$C = 273.15 + K$
where:
$C : Magnitude in Celcius Scale$
$K : Magnitude in Kelvin Scale$

Converting given temperature to kelvin scale, we get:
$K = 273.15 + 400$
$C = 673.15$

Hence, given temperature is ${673.15}^{\circ} C$

Suggest Corrections

Similar questions

Q. Convert the temperature of 373°C to the Kelvin scale.

Convert the following temperatures to Kelvin scale.

(a) 25°C

(b) 373°C

Q. Convert

50^{\circ} C

into Kelvin and Fahrenheit scale.

Q. Steam point is equal to

100^{\circ} C

, which is equal to ___ in Kelvin scale.

Convert the following temperature to Celsius scale:

(a) 300 K

(b) 573 K

Join BYJU'S Learning Program

Convert 400∘C to Kelvin scale.

The correct option is B 673.15 KUsing the temperature conversions: C=273.15+K where: C: Magnitude in Celcius Scale K: Magnitude in Kelvin Scale Converting given temperature to kelvin scale, we get: K=273.15+400 C=673.15 Hence, given temperature is 673.15∘C

Convert $400^{\circ} C$ to Kelvin scale.

The correct option is B $673.15 K$
Using the temperature conversions:
$C = 273.15 + K$
where:
$C : Magnitude in Celcius Scale$
$K : Magnitude in Kelvin Scale$

Converting given temperature to kelvin scale, we get:
$K = 273.15 + 400$
$C = 673.15$

Hence, given temperature is ${673.15}^{\circ} C$