Question

Convert ${45}^o$ into circular measure.

Answer 1

b'

Given, $D={45}^o$

We have, $\frac{D}{90}=\frac{R}{\frac{\pi }{2}}$

So, $\frac{45}{90}=\frac{R}{\frac{\pi }{2}}$

$\frac{1}{2}\times \frac{\pi }{2}=R$

$R=\frac{\pi }{4}$

Hence, circular measure of ${45}^o$ is $\frac{{\pi }^c}{4}$.

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