Question

Convert:
A. $3$-Methylaniline into
$3$-nitrotoluene

B. Aniline into $1,3,5$ -
tribromo benzene

Answer 1

A. $\text{Conversion of}3\text{-Methylaniline into}3\text{-nitrotoluene}$

For the conversion of $3$-Methylaniline into $3$-nitrotoluene first we are doing the diazotisation reaction in which $-N{H}_2$ will convert to $N_2^{+}C{l}^{-}$ and then reacts with fluoroboric acid followed by $NaN{O}_2/Cu/\Delta$ convert $N_2^{+}C{l}^{-}$ into the nitro group $(-N{O}_2)$ and evolution of dinitrogen gas occurs.

Involved reaction is shown as -



B.$\text{Conversion of Aniline into 1,3,5 - tribromobenzene}$

For the conversion of aniline $1,3,5$ - tribromo benzene, first we are doing the bromination of aniline in the presence of water which gives $2,4,6$ tribromo aniline, which on further reacting with nitrous acid $(273-278K)$ converts $N{H}_2$ into $N_2^{+}C{l}^{-}$.

After that, with the help of $H_{3}P{O}_2$/water we remove the $N_2^{+}C{l}^{-}$ group from the benzene ring via reduction and we get our final product $1,3,5$ tribromobenzene.

Involved reaction is shown below-