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Byju's Answer
Standard XII
Mathematics
Inverse of a Matrix
Convert [ 1...
Question
Convert
[
1
−
1
2
3
]
into an identity matrix by sutaible raw transformation
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Solution
A
=
[
1
−
1
2
3
]
Coverting into Identity matrix
I
=
[
1
0
0
1
]
R
2
→
R
2
−
2
R
1
[
1
−
1
2
−
2
(
1
)
3
−
2
(
−
1
)
]
[
1
−
1
0
5
]
R
2
→
R
2
5
⎡
⎣
1
−
1
0
5
5
⎤
⎦
[
1
−
1
0
1
]
Now,
R
1
→
R
1
+
R
2
[
1
+
0
−
1
+
1
0
1
]
[
1
0
0
1
]
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