Question

Convert each of the following into an improper fraction:
(a) $8\frac{7}{9}$
(b) $6\frac{3}{4}$

Answer 1

We have:
(a) $8\frac{7}{9}=\frac{\left(\right(8\times 9)+7}{9}=\frac{79}{9}$
(b) $6\frac{3}{4}=\frac{\left(\right(6\times 4)+3}{4}=\frac{27}{4}$