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Question

Convert each of the following into an improper fraction:
(i) 557
(ii) 938
(iii) 6310
(iv) 3511
(v) 10914
(vi) 12715
(vii) 8813
(viii) 5123

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Solution

We have:
(i) 557 = (5 × 7) + 57 = 407

(ii) 938 = (9 × 8) + 38 = 758

(iii) 6310 = (6 × 10) + 310 = 6310

(iv) 3511 = (3 × 11) + 511 = 3811

(v) 10914 = (10 × 14) + 914 = 14914

(vi) 12715 = (12 × 15) + 715 = 18715

(vii) 8813 = (8 × 13) + 813 = 11213

(viii) 5123 = (51 × 3) + 23 = 1553

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