Convert each of the following into an improper fraction-i 557ii 938iii 6310iv 3511v 10914vi 12715vii 8813 viii 5123

We have: (i) nbsp;557 #160;= #160;(5 #160; #215; #160;7) #160;+ #160;57 #160;= #160;407 (ii) nbsp;938 #160;= #160;(9 #160; #215; ...

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Byju's Answer

Standard X

Mathematics

Cartesian Product

Convert each ...

Question

Convert each of the following into an improper fraction:
(i) $5 \frac{5}{7}$
(ii) $9 \frac{3}{8}$
(iii) $6 \frac{3}{10}$
(iv) $3 \frac{5}{11}$
(v) $10 \frac{9}{14}$
(vi) $12 \frac{7}{15}$
(vii) $8 \frac{8}{13}$
(viii) $51 \frac{2}{3}$

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Solution

We have:
(i) $5 \frac{5}{7} = \frac{(5 \times 7) + 5}{7} = \frac{40}{7}$

(ii) $9 \frac{3}{8} = \frac{(9 \times 8) + 3}{8} = \frac{75}{8}$

(iii) $6 \frac{3}{10} = \frac{(6 \times 10) + 3}{10} = \frac{63}{10}$

(iv) $3 \frac{5}{11} = \frac{(3 \times 11) + 5}{11} = \frac{38}{11}$

(v) $10 \frac{9}{14} = \frac{(10 \times 14) + 9}{14} = \frac{149}{14}$

(vi) $12 \frac{7}{15} = \frac{(12 \times 15) + 7}{15} = \frac{187}{15}$

(vii) $8 \frac{8}{13} = \frac{(8 \times 13) + 8}{13} = \frac{112}{13}$

(viii) $51 \frac{2}{3} = \frac{(51 \times 3) + 2}{3} = \frac{155}{3}$

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Convert each of the following into an improper fraction: (i) 557 (ii) 938 (iii) 6310 (iv) 3511 (v) 10914 (vi) 12715 (vii) 8813 (viii) 5123

We have: (i) 557 = (5 × 7) + 57 = 407 (ii) 938 = (9 × 8) + 38 = 758 (iii) 6310 = (6 × 10) + 310 = 6310 (iv) 3511 = (3 × 11) + 511 = 3811 (v) 10914 = (10 × 14) + 914 = 14914 (vi) 12715 = (12 × 15) + 715 = 18715 (vii) 8813 = (8 × 13) + 813 = 11213 (viii) 5123 = (51 × 3) + 23 = 1553

Convert each of the following into an improper fraction:
(i) $5 \frac{5}{7}$
(ii) $9 \frac{3}{8}$
(iii) $6 \frac{3}{10}$
(iv) $3 \frac{5}{11}$
(v) $10 \frac{9}{14}$
(vi) $12 \frac{7}{15}$
(vii) $8 \frac{8}{13}$
(viii) $51 \frac{2}{3}$