Question

Convert from ${}^{o}F$ to ${}^{o}C$
${105}^{o}F$

Answer 1

As we know that,

$T_{℃}=\frac{5}{9}(T_{℉}-32)$

$T_{℉}=105℉\left(\text{Given}\right)$

Therefore,

$T_{℃}=\frac{5}{9}\times (105-32)$

$\Rightarrow T_{℃}=\frac{5}{9}\times 73=40.56℃$