Convert into factors $a^{2} + 4 a + 4 - b^{2} .$

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Solution

We have,
$a^{2} + 4 a + 4 - b^{2}$

$\Rightarrow (a + 2)^{2} - b^{2}$

We know that
$x^{2} - y^{2} = (x + y) (x - y)$

Therefore,
$\Rightarrow (a + 2 + b) (a + 2 - b)$

Hence, this is the answer.

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Similar questions

Factorise : $a^{2} + 4 a + 4 - b^{2}$

a^{2} + 4 a + 4

1 - (a^{2} + b^{2}) + a^{2} b^{2}

a^{2} + b^{2} - 2 a^{2} + c^{2} + 4 a

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