Convert the following Celsius temperature to kelvin scale
(i) $- 273^{0} C$
(ii) $30^{0} C$
(iii) ${- 100}^{0} C$
(iv) ${- 40}^{0} C$

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Solution

We know,
$K = C + 273$
Hence,
$- 273^{0} C = 273 - 273 = 0 K$
$30^{0} C = 273 + 30 = 303 K$
$- 100^{0} C = 273 - 100 = 173 K$
$- 40^{0} C = 273 - 40 = 233 K$

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Change the following celsius temperature to kelvin scale.

(i) – 273°C
(ii) – 100°C
(iii) – 40°C
(iv) + 30°C

Change the following celsius temperature to kelvin scale [2 MARKS]

(i) – 273°C
(ii) – 100°C
(iii) – 40°C
(iv) + 30°C

1. Convert the following temperature to Celsius scale.

(A)293 K

(B)470K

2. Convert the following temperature to kelvin scale.

(A)25degree C

(B)373degree C

5^{0} F

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