Convert the following equation in statement form
(i) $x - 5 = 9$
(ii) $5 p = 20$
(iii) $3 n + 7 = 1$

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Solution

(i) Subtract $5$ from $x$ gives $9$ .
(ii) $5$ times of $p$ is $20$ .
(iii) The sum of $3$ times $n$ and seven is $1$ .

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{log}_{2} 128 = 7

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\frac{- 64}{125}

\frac{- 345}{1024}

Convert the following products into factorials:
(i) 5.6.7.8.9.10 (ii) 3.6.9.12.15.18
(iii) (n+1)(n+2)(n+3) ...(2n) (iv) 1.3.5.7.9 ...(2n-1)

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