Question

Convert the following into exponential form :
i) ${\log }_{2}32=5$
ii) ${\log }_{3}81=4$

Answer 1

We know that $a^x=y⟹{\log }_{a}y=x$

(i) ${\log }_{2}32=5⟹2^5=32$

(ii) ${\log }_{3}81=4⟹3^4=81$