Question

Convert the following products into factorials.: $6\times 7\times 8\times 9$

Answer 1

$\frac{6\times 7\times 8\times 9(5\times 4\times 3\times 2\times 1)}{5\times 4\times 3\times 2\times 1}\Rightarrow \frac{9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}{5\times 4\times 3\times 2\times 1}\Rightarrow \frac{9!}{5!}$

Hence the correct value of above expression is $\frac{9!}{5!}$