Question

Coordinates of a square are :$(2,2),(-2,2),(-2,-2)$. Find the length of the diagonal.

• A. $8\sqrt{2}$
• B. $4$
• C. $4\sqrt{2}$
• D. None of these

Answer 1

The correct option is C $4\sqrt{2}$

Given vertices of square:

$A(2,2),B(-2,2),C(-2,-2),D(a,b)$

To find the diagonal AC

$AC=\sqrt{(2+2{)}^2+(2+2{)}^2}$

$AC=\sqrt{16+16}$

$AC=\sqrt{32}$

$AC=4\sqrt{2}$