Coordinates of centre and radius of the circle $(x - 3)^{2} + (y + 4)^{2} = 25$ are respectively

(3, 4)

25

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(- 3, 4)

5

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(3, - 4)

5

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(3, - 4)

25

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Solution

The correct option is C $(3, - 4)$ , $5$
$(x - 3)^{2} + (y + 4)^{2} = 25$
$(x - 3)^{2} + (y - (- 4))^{2} - (5)^{2}$
$(x - 4)^{2} + (y - k)^{2} - (r)^{2}$
$r = 5 (h, k) = (3, - 4)$

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{(x + 3)}^{2} + {(y - 4)}^{2} = 25

x = 5 - 5 sin t

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x^{2} + y^{2} = 25.

Q

R

(3, 4)

(- 4, 3),

∠ Q P R

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