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Flexidentate Ligands

Coordination ...

Question

Coordination number of $C r$ in $K_{3} [C r (C_{2} O_{4})_{3}]$ is :

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Solution

$K_{3} [C r (C_{2} O_{4})_{3}]$
As oxalate are bidentate ligand, so the coordination number of $C r$ is $3 \times 2 = 6$ .

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