Coordination number of Nickel in $[N i (C_{2} O_{4})_{3}]^{4 -}$ is:

3

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12

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6

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4

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Solution

The correct option is D $6$
Oxalate is an example for bidentate ligand, three oxalate ligands form six-coordinate bonds around the $N i^{2 +}$ ion.

Co-ordinate number of Nickel in $[N i (C_{2} O_{4})_{3}]^{4 -}$ is $3 \times 2 = 6.$

The coordination number is six.

Hence, option $C$ is correct.

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