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Byju's Answer

Standard XII

Chemistry

Central Atom and Ligands

Copper contai...

Question

Copper containing alloy of weight $0.3175 g$ is dissolved in an acid and an excess of $K I$ is added. Estimation of copper in alloy is based on the following reaction:

$2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)$

${I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)$

$I_{2}$ formed is converted to $K I_{3}$ in the given reaction. This shows that $I_{2}$ is :

soluble in

H_{2} O

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lewis acid

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ionic compound

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lewis base

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Solution

The correct option is D lewis acid
In this reaction, $I^{-}$ donates a pair of electrons to $I_{2}$ molecule to form ${I_{3}}^{-}$ .
Hence, iodine is a "Lewis acid" and iodide is a "Lewis base".

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Similar questions

Copper containing alloy of weight

0.3175 g

is dissolved in an acid and an excess of

K I

is added. Estimation of copper in alloy is based on the following reactions:

2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)

{I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)

Estimation is based on :

Copper containing alloy of weight

0.3175 g

is dissolved in an acid and an excess of

K I

is added. Estimation of copper in alloy is based on the following reaction:

2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)

{I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)

Oxidising agent (

O

) and reducing agent (

R

) in the above reaction are :

2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)

{I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)

When copper containing alloy of weight

0.3175 g

is dissolved in an acid and an excess of

K I

is added,

25

mL of

0.10 M N a_{2} S_{2} O_{3}

is required, then Cu present in alloy is_________.

Q. After dissolving

0.20

g sample of the alloy in acid, an excess of

K I

is added and the

C u^{2 +}

and

I^{-}

ions undergo the reaction:

C u^{2 +} (a q) + I^{-} (a q) \to C u I (s) + I_{3}^{-} (a q)

I_{3}^{-} (a q) + S_{2} O_{3}^{2 -} (a q) \to S_{4} O_{6}^{2 -} (a q) + 3 I^{-} (a q)

20

ml of

0.1 M

N a_{2} S_{2} O_{3}

is required for the titration to the equivalent point, what is the weight percent of

C u

in the alloy?

Balance the following redox reactions by ion-electron method:

(a) (aq) + I^– (aq) → MnO₂ (s) + I₂(s) (in basic medium)

(b) (aq) + SO₂ (g) → Mn²⁺ (aq) + (aq) (in acidic solution)

(d) + SO₂(g) → Cr³⁺ (aq) + (aq) (in acidic solution)

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The correct option is D lewis acidIn this reaction, I− donates a pair of electrons to I2 molecule to form I3−.Hence, iodine is a "Lewis acid" and iodide is a "Lewis base".

The correct option is D lewis acid
In this reaction, $I^{-}$ donates a pair of electrons to $I_{2}$ molecule to form ${I_{3}}^{-}$ .
Hence, iodine is a "Lewis acid" and iodide is a "Lewis base".