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Density

Copper crysta...

Question

Copper crystallises into a fcc structure and the unit cell has length of edge $3.61 \times 10^{- 8} c m$ calculate the density of copper if the molar mass of Cu is $63.5 g m o l^{- 1}$ .

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Solution

Given that

Length of edge, $a = 3.61 \times 10^{- 8} c m$

Atomic mass of cupper, $M = 63.55 g / m o l$

Avogadro constant, $N A = 6.022 \times 10^{23} p e r m o l$

Number of atoms in unit cell of $F C C, Z = 4$

Use formula of density-
$p = \frac{Z M}{a^{3} N_{A}}$

Plug the values in this formula we get-
$p = 8.92 g m / c m^{3}$

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