Copper forms two oxides following law of variable proportions. One gram of each oxide in hydrogen gas gave $0.799 g$ and $0.888 g$ of the metal respectively. Give the composition of these oxides.

Open in App

Solution

Let the two oxides of Cu be named A and B
oxide A
mass of Cu in 1g of oxide A = 0.888g
mass of O in 1g of oxide A =1-0.888=0.112g
oxide B
mass of Cu in 1g of oxide B = 0.799g
mass of O in g of oxide B = 1-0.799=0.201g
In oxide A , 1g Cu is combined with oxygen = 0.112 x 1/0.888 = 0.126g
In oxide B , 1g Cu is combined with oxygen = 0.201 x 1/0.799 = 0.252g
the different weight of oxygen combined with a fixed weight (1g) of Cu are in ratio 0.126: 0.252 or 1: 2
This is a simple whole ratio that shows the agreement with the law of multiple properties.

Suggest Corrections

Similar questions

Q. Two oxides of certian metal were separetly heated in a current of hydrogen untill constant weights were obtained . The.water produces in each case was carefully collected and weighed . 2 grams of each oxide gave respectively 0.2517 grams and 0.4526 grams of water .show that these results establosh the law of multiple proportions.

A metal forms two oxides, the higher oxide contains 80% metal, 0.72g of the lower oxide gave 0.8g of higher oxide on heating. Show that the data illustrates the law of multiple proportions?

Join BYJU'S Learning Program

Copper forms two oxides following law of variable proportions. One gram of each oxide in hydrogen gas gave 0.799g and 0.888g of the metal respectively. Give the composition of these oxides.

Copper forms two oxides following law of variable proportions. One gram of each oxide in hydrogen gas gave $0.799 g$ and $0.888 g$ of the metal respectively. Give the composition of these oxides.