Copper forms two oxides. For the same amount of copper, twice as much oxygen was used to form the first oxide than to form the second one. What is the ratio of the valences of copper in the first and second oxides?

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Solution

Let us consider the problem:
$C o p p e r (I I) o x i d e - C u O;$
Therefore,
$c o p p e r v a l e n c e - 2 C o p p e r (I) o x i d e - C u_{2} O;$
Hence,
$c o p p e r v a l e n c e - 1 R a t i o : 2$

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