Copper (II) ions gives reddish brown precipitate with potassium ferrocyanide. The formula of the precipitate is:

{C u}_{4} [F e {(C N)}_{6}]

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{C u}_{2} [F e {(C N)}_{6}]

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{C u}_{3} [F e {(C N)}_{6}]

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{C u}_{3} {[F e {(C N)}_{6}]}_{2}

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Solution

The correct option is B ${C u}_{2} [F e {(C N)}_{6}]$
With potassium ferrocyanide, copper(II) ions forms reddish brown precipitate of cupric ferrocyanide.
$2 C u S O_{4} + K_{4} [F e (C N)_{6}] \to C u_{2} [F e (C N)_{6}] r e d d i s h b r o w n p r e c i p i t a t e ↓ + 2 K_{2} S O_{4}$ .

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