Copper sulphate reacts with sodium hydroxide to form a blue precipitate of copper hydroxide and sodium sulphate. In an experiment, 15.95 g of copper sulphate reacted with 8.0 g of sodium hydroxide to form 9.75 g of copper hydroxide and 14.2 g of sodium sulphate. Which law of chemical combination is illustrated by this data?

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Solution

1. The law of conservation of mass is illustrated by this data.
2. The mass of products = The mass of reactants
CuS $O_{4}$ + NaOH → Cu ${(O H)}_{2}$ + NaS $O_{4}$
(15.95 g) (8 g) (9.75 g) (14.2 g)
3. Total mass of reactants = (15.95 g + 8 g) = 23.95 g
4. Total mass of products = (9.75 g + 14.2 g) = 23.95 g
5. The total mass of products is equal to the total mass of reactants
Hence, the Law of conservation of mass is valid here.
Law of conservation of mass
The law of conservation of mass states that the mass can neither be created nor destroyed but is transformed from one form to another
It can also be described as in a chemical reaction mass is neither created nor destroyed, that is the mass of reactants is equal to the mass of the products.

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