Copper sulphate solution is electrolysed between two platinum electrodes. A current is passed until $1.6 g$ of oxygen is liberated at anode. The amount of copper deposited at the cathode during the same period is : [At.mass of $C u = 63.6$ ]

6.36 g

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63.6 g

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12.7 g

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3.2 g

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Solution

The correct option is B $6.36 g$
Given Data : 1) $W e i g h t$ $o f$ $O_{2}$ = $1.6$ $g$
2) $E q u i v a l e n t$ $W e i g h t$ $o f$ $O_{2}$ = $8$ $g$
3) $E q u i v a l e n t$ $W e i g h t$ $o f$ $C u$ = $31.5$ $g$
To Find: $W e i g h t$ $o f$ $C u$ = ?

We know that,
$\frac{W t . o f C u}{W t . o f O_{2}}$ = $\frac{E q . w t . o f C u}{E q . w t . o f O_{2}}$

Substituting the given values we get,

$\frac{W t . O f C u}{1.6}$ = $\frac{31.5}{8}$

Wt.of $C u$ = $\frac{31.5 \times 1.6}{8}$

= $6.38$ g

Hence the correct option is 'A'.

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