Copy the diagram given below and complete the path of light ray till it emerges out of the prism. The critical angle of glass is $42^{o}$ . In your diagram mark the angles wherever necessary.

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Solution

The diagram is shown. The ray $P Q$ enters the prism from the side $A B$ , its angle of incidence is $0 °$ . Thus it does not undergo any refraction. Its angle of refraction is also $0 °$ . When this light ray reaches the base of the prism (BC), its angle of incidence (on the boundary $B C$ ) is $60 °$ which is more than its critical angle ( $42 °$ ). Thus this incident light ray ( $Q R$ ) does not enter into the next medium, instead it undergoes total internal reflection. When this reflected light ray ( $R S$ ) reaches the side $A C$ , its angle of incidence is $0 °$ . Again, it does not undergo any refraction, which causes the angle of emergence to become $0 °$ .

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Copy the diagram given below and complete the path of light ray till it emerges out of the prism. The critical angle of glass is 42o. In your diagram mark the angles wherever necessary.

Copy the diagram given below and complete the path of light ray till it emerges out of the prism. The critical angle of glass is $42^{o}$ . In your diagram mark the angles wherever necessary.