Question

Corner points of the feasible region determined by the system of linear constraints (0, 3), (1, 1) and (3, 0). Let z = px + qy, where p, q > 0. Condition on p and q so that the minimum of z occurs at (3, 0) and (1, 1) is
(a) p = 2q
(b) 2p = q
(c) p = 3q
(d) p = q

Answer 1

Since minimum of z = px + qy where p, q > 0 occur at (3, 0) and (1, 1)
Z_min (3, 0) = Z_min (1, 1)
i.e. p(3) + q(0) = p + q
i.e. 2p = q
Hence, the correct answer is option B.