Correct and balance the following reactions :

(a) Ca + $H_{2}$ $⟶$ CaOH + H

(b) N + H $⟶$ $N H_{3}$

Open in App

Solution

(a)

The basic equation is

$C a O + H_{2} O ⟶ C a (O H)_{2} + H_{2}$

Here the number of hydrogen (H) atoms and number of oxygen (O) atoms on both side are different. So we give 2 molecules of H2O on left hand side.

So the balanced equation becomes,

$C a O + 2 H_{2} O ⟶ C a (O H)_{2} + H_{2}$

(b)

The basic equation is

$N_{2} + H_{2} ⟶ N H_{3}$

Both hydrogen and nitrogen atoms are different on both sides.We first put 2 as coefficient on $N H_{3}$ . Ans then we balance hydrogen on left hand side.
So the balanced equation is,

$N_{2} + 3 H_{2} ⟶ 2 N H_{3}$

Suggest Corrections

Similar questions

Ca + H_{2} O \underset{}{\to} CaOH + H

N + H \underset{}{\to} {NH}_{3}

{C l O}_{3}^{-} + I^{-} + {6 H}^{+} ⟶

{C l O}_{3}^{-} + {F e}^{2} + H^{+} ⟶

{Z n ({C l O}_{3})}_{2} Δ \to

O_{3} + I_{2} + H_{2} O ⟶

{K B r O}_{3} + F_{2} + K O H ⟶

N_{2} + H_{2} \Rightarrow N H_{3}

H {N O}_{3} + C a {(O H)}_{2} \to C a {({N O}_{3})}_{2} + H_{2} O

N a C l + A g {N O}_{3} \to A g C l + N a {N O}_{3}

B a {C l}_{2} + H_{2} {S O}_{4} \to B a {S O}_{4} + H C l

N_{2} + H_{2} \to {N H}_{3}

Join BYJU'S Learning Program