Correct code for the following thermal composition reaction(s) evolving gas having equal number $σ$ and $π$ bonds is:
(i) $B e C O_{3} Δ - \to$

(ii) $Z n S O_{4} Δ - ---- \to T < 800^{o} C$

(iii) $F e S O_{4} 300^{o} C - -- \to$

(iv) $(N H_{4})_{2} C r_{2} O_{7} Δ - \to$

i, ii

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i, iii, iv

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i, ii, iii

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all of these

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Solution

The correct option is B i, ii, iii
$B e C O_{3} Δ - \to B e O + C O_{2}$

$2 Z n S O_{4} Δ - ---- \to T < 800^{o} C 2 Z n O + 2 S O_{2} + O_{2}$

$2 F e S O_{4} 300^{o} C - -- \to F e_{2} O_{3} + S O_{2} ↑ + S O_{3} ↑$

$(N H_{4})_{2} C r_{2} O_{7} Δ - \to N_{2} + C r_{2} O_{3} (g r e e n) + 4 H_{2} O$

$C O_{2}, S O_{2}, O_{2}, S O_{3}$ gases contains same number of sigma and pi bonds. On the other hand, nitrogen contains different number of sigma and pi bonds.
Hence, the correct code for the following thermal composition reaction(s) evolving gas having equal number and bonds is i, ii, iii.

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Correct code for the following thermal composition reaction(s) evolving gas having equal number σ and π bonds is:(i) BeCO3Δ−→(ii) ZnSO4Δ−−−−−→T<800oC(iii) FeSO4300oC−−−→(iv) (NH4)2Cr2O7Δ−→

Correct code for the following thermal composition reaction(s) evolving gas having equal number $σ$ and $π$ bonds is:
(i) $B e C O_{3} Δ - \to$

(ii) $Z n S O_{4} Δ - ---- \to T < 800^{o} C$

(iii) $F e S O_{4} 300^{o} C - -- \to$

(iv) $(N H_{4})_{2} C r_{2} O_{7} Δ - \to$